The solution of the system can be found using the Gauss-Jordan elimination. Recall that when using Gauss-Jordan elimination, the end goal is to obtain an identity matrix for the coefficient matrix by using elementary row operations. Notice column 1 already has a 1 and then 2 zeros. So next we focus on obtaining a 1 in row 2, column 2. This can be achieved by adding row 3 to row 2 and putting the result in row 2. 1131 1 1 3 1 0419>o| x |x9 0360 0 3 6 o A system of linear equations and a reduced matrix for the system are given. 2 10 10 xy +z=4 3 3 3x +22=10 1 2 x4y+22=6 01? _ 00 0 0 (a) Use the reduced matrix to find the general solution of the system, if one exists. (If there is no solution, enter N0 SOLUTION. If there are infinitely many solutions, express your answers in terms of 2 as in Example 3.) (lelz)=( ) X (b) If multiple solutions exist, find two specific solutions. (Enter your answers as a comma-separated list of ordered triples. If there is no solution, enter NO SOLUTION.) (XIyIZ)=