Question: The total power required to perform a rolling operation using two-high rolls is 900 kW. The draft is 10 mm, and the starting plate
The total power required to perform a rolling operation using two-high rolls is 900 kW. The draft is 10 mm, and the starting plate is 30 mm thick, 300 mm wide, and 3000 mm long. If roll radius = 600 mm, then what is the rotational speed of the rolls performing this operation? Strength coefficient = 500 MPa, and strain hardening exponent = 0.25.
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SOLUTION To determine the rotational speed of the rolls performing the rolling operation we need to use the following equation rotational speed in rev... View full answer
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