The velocity of a particle moving along a line is given by v(t)=t³-4t² meters per second. Find the displacement of the particle during the time interval between -2 and 6 seconds.
 
 Displacement = (Include the correct units.)
 
 To find the total distance traveled by the particle during the time interval from -2 to 6 seconds, we must split the integral of the absolute value of velocity into a sum of two integrals
 
 Total distance traveled = ∫|t3−4t2|dt| upper limit is 6 & lower limit is -2. =∫v1(t)dt| (upper limit is k & lower limit is -2)+∫v2(t)dt (upper limit is 6 & lower limit is k)
 
 where v1(t) and v2(t) are functions and k is a number such that
 
 v1(t)= (Absolute values are not allowed.)
 v2(t)= (Absolute values are not allowed.)
 k=