this is character decoding

can you please do this in Java.

thank you

attached is the question and the program to reference

import java.util.Scanner;

public class Ass11 {

static String removePunctuation(String str) {

return str.replaceAll("\\W", "");

}

static String removeWhiteSpace(String str) {

return str.replaceAll("\\s", "");

}

static String lowerCaseConverter(String str) {

return str.toLowerCase();

}

static String shift4Operation(String str) {

String str2="";

int a;

for(int i=0; i

a = (int)str.charAt(i);

a = a+4;

if(a>122) {

int s = a - 123;

a = 97 + s;

}

str2 = str2 + (char)a;

}

return str2;

}

static String upperCaseConverter(String str) {

return str.toUpperCase();

}

static String[] hexaConverter(String str) {

int a;

String[] str2 = new String[str.length()];

for(int i=0; i

a = (int)str.charAt(i);

str2[i] = "0x"+Integer.toHexString(a);

}

return str2;

}

static String[] evenOdd(String [] str, int length) {

int a =0;

String[] str2 = new String[length];

for(int i=0; i

str2[a] = str[i];

a++;

}

for(int i=1; i

str2[a] = str[i];

a++;

}

return str2;

}

public static void main(String[] args) {

String str;

String str2;

String [] str3;

Scanner sc = new Scanner(System.in);

System.out.print("Input : ");

str = sc.nextLine();

str = removeWhiteSpace(str);

System.out.println("Step 1: After Remove WhiteSpace : "+str);

str = removePunctuation(str);

System.out.println("Step 2: After Remove Punctuation : "+str);

str = lowerCaseConverter(str);

System.out.println("Step 3: Case Folding : "+str);

str = shift4Operation(str);

str2 = upperCaseConverter(str);

System.out.println("Step 4: Shift : "+str+" CaseFolding "+str2);

str3 = hexaConverter(str2);

System.out.print("Step 5: Hex Values are : ");

for (int i = 0; i

System.out.print(str3[i] + " , ");

}

str3 = evenOdd(str3,str3.length);

System.out.println("Listing even position first, then the odd : ");

for (int i = 0; i

System.out.print(str3[i] + " , ");

}

System.out.println();

System.out.print("Step 6: Current ciphertext is : ");

for (int i = 0; i

System.out.print(str3[i] + " , ");

}

System.out.println("Printing in group of 5 : ");

for (int i = 0; i

if(i % 5 == 0 && i!=0) {

System.out.println();

}

System.out.print(str3[i] + " ");

}

}

}

Write a program that decrypts the output created by the program you wrote for assignment 4 by reversing the steps. NOTE: you won't be able to recover whitespace, punctuation symbols or original case this way! Example Given an input @x4 BX50 Ox530x530x50 Bx49 6x500x410x560x48 stop 1. Create a new list of values in the right order 0x4 BX49 X5 X500X530x410x530x560x500x48 step 2. Shift four positions to the left mod 26) x 48 @x45 Bx4c 6x4c 8x4f Ox570x4f ex52x400x44 Step 3. Convert back to characters using UTF-8 encoding HELLO WORLD