Question: This is only one question, I explained the question in the detailed formated with instructions and example, you only have to edit the given code

This is only one question, I explained the question in the detailed formated with instructions and example, you only have to edit the given code to get the similar output in the example. Please help answer it in step by step format. Thank you!!

Determine whether an undirected graph is a tree using depth-first search. An undirected graph is a tree if and only if the graph contains no cycles. For example, this is a tree because it contains no cycles:

This is only one question, I explained the question in the detailed

While this graph contains cycles and therefore is not a tree:

formated with instructions and example, you only have to edit the given

C program: Write a depth-first search through a graph to determine whether the graph contains cycle. A cycle is detected when depth-first search find a graph node that was already visited.

Input format: Program should take a single command line argument specifying the path to an input file. Test cases for this program are in the tests/ directory. In each test case, the first line records the number of nodes N in the graph. Then, the adjacency matrix is recorded in the subsequent N rows of the file.

Output format: Should print "yes" if the graph is a tree, "no" if the graph is not a tree.

Edit the given code below:

#include "../graphutils.h" // header for functions to load and free adjacencyList

// A program to determine whether an undirected graph is a tree

// A recursive function that returns true if no cycles found

bool isTreeDFS (

size_t graphNodeCount,

AdjacencyListNode* adjacencyList,

bool* visited,

graphNode_t parent,

graphNode_t current

) {

// First see if current node has already been visited, indicating a cycle found

/* ... */

// Current node was not already visited, so now mark it as visited

/* ... */

// Now iterate through each of the neighboring graph nodes

AdjacencyListNode* neighbor = adjacencyList[current].next;

while (neighbor) {

if (neighbor->graphNode!=parent) {

// If the neighbor nodes is not the parent node (the node from which we arrived at current), call DFS

/* ... */

}

neighbor = neighbor->next;

}

// All DFS searches from current node found no cycles, so graph is a tree from this node

return true;

}

int main ( int argc, char* argv[] ) {

// READ INPUT FILE TO CREATE GRAPH ADJACENCY LIST

AdjacencyListNode* adjacencyList = NULL;

/* ... */

// Array of boolean variables indicating whether graph node has been visited

bool* visited = calloc ( graphNodeCount, sizeof(bool) );

/* ... */

/* ... */

printf(isTree ? "yes" : "no");

return EXIT_SUCCESS;

}

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