This is the bomb lab phase2, I just have no idea on how to solve it. I know the answer is a six number array, I want to know what numbers they are?

6x00000000004015d7 : pop %rbx 0x00000000004015d8 : retq of assembler dump. b) stepi 00401572 in phase2 ) db) disas mp of assenbler code for function phase2: %rbx $0x20,%rsp %fs:0x28,%rax %rax,0x18(%rsp) %eax , %eax %rsp,Krst 0x000000000040154f : 0x0000000000401550 : 0x0000000000401554 : push sub nov 6x000000000040155d : 21: ex0000000000401567 : oxogeoooo00040156c : : 6x0000000000401575 : 0x0000000000401577 : ox0000e0000040157C : 0x0000000000401581 50: 0x0000000000401586: 6x000000000040158e : : 0x0000000000401598 : 6x0000000000401599 ROV0x204d8e(xrip) cnp je nov callq nov jnp novs1q nov lea cl 6x0000000000401562 0x0000000000401564 # 6x686300 %ebx,Krax (Krsp,%rax,4),%ecx 6x1(%rbx),%eax > 6x0000000000401572 bonbo tq nov nov cltd ?div 6x0000000000401593 0x0000006000401596 (%rsp,%rax,4),%esi Kecx, xeax %est # 6x606304 phase2 data+4> 0x000000000040159b : cmp 0x204d63(Srip),xeax 0xoooeoo0000415a1 : jne ex4015ac x00000000004015a5 87: : idiv %est test %edx ,%edx sexe ,%eax sex1,%ebx 0x80000000004015ac 6x00000000004015b6 103: add 0xe0000860004015b9 : callq ex400ea 0xeeee6o60004015d3 : 125: xor je ex 18(%rsp),%rax %fs:0x28,%rax 0x4015d3 0x00000000004015d7 0xe0000600004015d8 : pop %rbx End of assembler dump (adb) x Seax