This problem will require use of the formulas below: Nth partial Fourier series for a periodic function f(x) with period 2L is FN (2) = ao + EN 1 [a, cos (7) + b sin ()] FN ( x ) = a0+{n=1N[ancos (nxxL) + bn sin ( n+xL)] where an = b = bn ao = L f(x) dx a 0 = 12LS - LLf(x) dx, f(x) cos(7)dxan = 1 LS - LL f (x) cos (nxL)dx, L f(x) = f(x) sin() dx bn = 1 LS - LL f (x) sin (nxL) dx L For the rest of this problem, [-2 if-2 x < 0 " 0 if 0 < x < 2 f(x + 4) = f(x) f(x)=(-2if-2