This test: 52 point(s) Test: Test 7 Question 14 of 16 > possible This question: 5 point(s) possible Submit test Match these values of r with the accompanying scatterplots: 1, 0.77, - 0.77, 0.997, and - 0.41. Click the icon to view the scatterplots. X Scatterplots Match the values of r to the scatterplots. Scatterplot 1 Scatterplot 2 Scatter Scatterplot 1, r = Scatterplot 2, r= 8- 8- Scatterplot 3, r = Scatterplot 4, r = Scatterplot 5, r= 2- 0 0 2 0.4 0.6 0.8 1 0 02 04 0.6 0.8 0 0.2 04 0 Scatterplot 4 Scatterplot 5 15 14- 13 12- 11+ 10- 0 02 04 0.6 08 0.2 0.4 0.6 0.8 1Test: Test 7 This test: 52 point(s) possible This question: 4 point(s) possible Submit test The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 51 inches. Is the result close to the actual weight of 575 pounds? Use a significance level of 0.05. Chest size (inches) 47 46 49 50 38 Weight (pounds) 48 487 496 546 518 397 510 Click the icon to view the critical values of the Pearson correlation Critical Values of the Pearson Correlation Coefficient r Critical Values of the Pearson Correlation Coefficient r What is the regression equation? n a = 0.05 o = 0.01 NOTE: To test Ho: p = 0 0.950 0.990 against H,: p# 0, reject Ho y = [+x(Round to one decimal place as needed.) 0.878 0.959 0.811 if the absolute value of r is 0.917 0.754 greater than the critical What is the best predicted weight of a bear with a chest size of 51 inc 0.875 value in the table. 8 0.707 0.834 9 The best predicted weight for a bear with a chest size of 51 inches is 0.666 0.798 10 0.632 0.765 (Round to one decimal place as needed.) 11 0.602 0.735 Is the result close to the actual weight of 575 pounds? 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 O A. This result is not very close to the actual weight of the bear. 15 0.514 0.641 O B. This result is very close to the actual weight of the bear. 16 0.497 0.623 17 0.482 0.606 O C. This result is close to the actual weight of the bear. 18 0.468 0.590 O D. This result is exactly the same as the actual weight of the bear 19 1.456 0.575 20 0.444 0.561 25 0.396 0.505 30 0.361 0.463 35 0.335 0.430 40 0.312 0.402 45 0.294 0.378