this the quistion witth all deatails

Important - The design temperature of the different spaces of the floor are given in table 1. - The table 2 give the value for the coefficient ai according to the nature of the neighboring wall. - The table 3 gives the thermal characteristics of the internal/external walls. The main objective of this exercise is to estimate the heat losses from the "room 1 " and to calculate the number of the radiators elements needed to maintain the temperature of the "room 1 " at Ti and the temperature outside the house is To. We have to notice also that the level above the "room 1 " is at the same temperature Tl. The floor is in contact with the ground. Heat losses through walls a) Write the formula and calculate the different surfaces and the different conductance's ( U factors). b) Calculate the heat losses through the different faces and fill the table 4 . 1. Heat losses due to infiltrations c) Calculate the heat losses due to infiltration for the "room 1 ". 2. Number of elements and reparation of the radiators Table 3: Composition of the external wall 2. Number of elements and reparation of the radiators d) Calculate the total heat losses of the "room 1 ". c) Take a safe factor of 15% and calculate the total heat needed by your "room 1 " for these design conditions. f) Estimate the number of radiators and the number of elements that should be installed in the "room 1 ". We notice here that the power of a radiator element is P50= 150 Watts. Table 4: IIcat losses for the "rouan 1