To solve for forces in statically indeterminate bars with axial loads.

When the number of reaction forces is greater than the number of equilibrium equations, the system is statically indeterminate. Solving for the reactions requires some additional equations. These additional equations come from considering compatibility relationships $($i$.$e$,$ continuity of displacements and relationships between displacements and loads$).$ For an axially loaded member, the compatibility relationship for the deflections can be written by setting the total relative axial displacement between the ends of the member to a known value. The load$-$displacement relationship $={\displaystyle \underset{?}{\overset{?}{}}}\frac{NL}{AE}$ gives another equation for the deflections. Once the internal normal force of each segment is written in terms of the end reactions and applied loads, there is enough information to solve for the reactions.

Figure is the applied force?

Express your answer with appropriate units to three significant figures.

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Part B $-$ Reaction with a known load Express your answer with appropriate units to three significant figures.

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$F_A^H+h+O?$

Part C $-$ Load point for equal forces

Consider the structure from Part $B($Figure $2).$ What value of $x$ will lead to equal reaction forces at A and $B?$

Express your answer in meters to three significant figures.

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A

C $B$

$1012(2)$

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