Question: To transform the function h 0 ( y ) = y h 0 (y)=y into h ( y ) = e ln ( y 5

To transform the function h 0 ( y ) = y h 0 (y)=y into h ( y ) = e ln ( y 5 ) h(y)=e ln(y5) , follow these steps: Step 1: h 1 ( y ) h 1 (y) Function: h 1 ( y ) = y 5 h 1 (y)=y5 Description: This is a horizontal shift to the right by 5 units. Step 2: h 2 ( y ) h 2 (y) Function: h 2 ( y ) = ln ( y 5 ) h 2 (y)=ln(y5) Description: This applies the natural logarithm to the function, transforming it into a logarithmic function. Step 3: h 3 ( y ) h 3 (y) Function: h 3 ( y ) = e ln ( y 5 ) h 3 (y)=e ln(y5) Description: This applies the exponential function to the logarithm, effectively reversing the logarithm and resulting in h ( y ) = y 5 h(y)=y5. (b) Domain and Roots Domain of h ( y ) h(y): Since ln ( y 5 ) ln(y5) is defined for y 5 > 0 y5>0, the domain is y > 5 y>5. Roots: There are no roots because e ln ( y 5 ) = y 5 e ln(y5) =y5 is never zero for y > 5 y>5. (c) Sketch of h ( y ) h(y) Graph: The function h ( y ) = y 5 h(y)=y5 is a linear function with a slope of 1, starting at y = 5 y=5. It is a straight line with a y-intercept at (5, 0) and continues indefinitely to the right. If you need further clarification or help, feel free to ask! Explain bout graph

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