Trial Force used (N) Time (S) Distance (M) Acceleration Mass (kg) (Fixed) (m/s^2) 1 150 N 5.94 5.0 0.283 530 2 50 N 9.71 5.0 0.106 471.7 3 100 N 6.99 5.0 0.205 975.6 Analysis 1. Using the equation d=1/2at^2, the value of 5.0 m for the distance, and the time that you recorded for wagon to reach the stop block, calculate the acceleration for each trial. Show your work. Fill in Table 1 with your answers D=at^2/2=a=2d/t^2 Trial 1: D=5m, t=5.94 seconds, a=2x5/5.94 seconds 2-0.283m/s^2 Trial 2: D=5m, t=9.71 seconds, a=2x5/9.71 seconds 2=0.106m/s^2 Trial 3: D=5m, t=6.99 seconds, a=2x5m/6.99 seconds^2=0.205m/s^2 2. Using Newton's second law of motion, calculate the mass of the cart for each trial. Show your work. Fill in Table I with your answers. Newtons second law of motion: m=fa instead of f-ma Trial 1: F=150N, a=0.283m/s^2 M=150/0.283m/s^2-530kg Trial 2: F=50 N, a=0.106m/s^2 M=50/0.106m/s^2=471.7kg Trial 3: F=100 N, a=0.205m/s^2 M=100/0.205m/s^2-975.6kg Questions Answer all the questions in complete sentences 1. Compare the accelerations for the three trials. Explain how Newton's second law was demonstrated in the simulation? 2. Describe how Newton's first and third laws would apply to this situation if this simulation was done in the real world. 3. Compare the masses that you calculated for the three trials. If the actual mass of the cart did not change (same cart for all trials), what measurement do you believe contributed the largest amount of error to that calculation? Explain your