Two parallel plates have a potential difference of $14\mathrm{.}0V.$

a$.$ What would the Potential energy in $eV$ for a proton a at the surface of the positive plate?

b$.$ What would the energy be in Joules?

$2\mathrm{.}24{10}^{-18}J$

c$.$ If a proton is released from the positive plate and allow to jump straight across the gap, what would be its velocity as it reached the negative plate?

$51,800\frac{m}{s}$

$($The mass of a proton is $1\mathrm{.}67{10}^{-27}kg.)$