Question: Unit 5 Assignment Started: Sep 21 at 3:51pm Quiz Instructions Please choose one response for each question. There are 30 questions, and there is no

Unit 5 Assignment Started: Sep 21 at 3:51pm Quiz Instructions Please choose one response for each question. There are 30 questions, and there is no time limit. There are no retakes. You will be able to see the correct answers, but these will only be available until the START of midterms (October 2nd at 11:59 pm). Question 1 1 pts What's the minimum number of hypotheses necessary for a statistical test? 1 3 30 0 2 4 Question 2 1 pts The average private university in America charges tuition of $100,000 a year, but a sample of forty ocial college board Gold Plated Luxury Colleges assesses an average tuition of $400,000. The sample standard deviation is $35,400. What's the appropriate statistical test? independent means matched or paired samples one-sample test single proportion two proportions Question 3 1 pts A study tests whether teenagers sleep more than adults on average. A sample of 16 teenagers has a mean of 8.9 hours slept and a standard deviation of 1.2. A sample of 12 adults has a mean of 6.9 hours slept and a standard deviation of 0.6. Indicate if the hypothesis test is for __________. independent sample means, population standard deviations known single mean matched or paired samples independent sample means, population standard deviations unknown Question 4 1 pts When studying gender dierences in teen behavior, researchers have collected data implying that teenage girls use more ring tones on their cellular phones than teenage boys do. In one particular study of 40 randomly chosen teenage girls and boys (20 of each) with cellular phones, the mean number of ring tones for the girls was 3.2 with a standard deviation of 1.5. The mean for the boys was 1.7 with a standard deviation of 0.8. Conduct a hypothesis test to determine if the means are approximately the same or if the girls' mean is higher than the boys' mean. Denote the girls as \"G\" and the boys as \"B\". What is the null hypothesis? G-B =0 G-B <0 g-b> 0 G-B 0 Question 5 1 pts When studying gender dierences in teen behavior, researchers have collected data implying that teenage girls use more ring tones on their cellular phones than teenage boys do. In one particular study of 40 randomly chosen teenage girls and boys (20 of each) with cellular phones, the mean number of ring tones for the girls was 3.2 with a standard deviation of 1.5. The mean for the boys was 1.7 with a standard deviation of 0.8. Conduct a hypothesis test to determine if the means are approximately the same or if the girls' mean is higher than the boys' mean. Denote the girls as \"G\" and the boys as \"B\". What is the alternative hypothesis? G-B 0 G-B <0 g-b> 0 Question 6 1 pts When studying gender dierences in teen behavior, researchers have collected data implying that teenage girls use more ring tones on their cellular phones than teenage boys do. In one particular study of 40 randomly chosen teenage girls and boys (20 of each) with cellular phones, the mean number of ring tones for the girls was 3.2 with a standard deviation of 1.5. The mean for the boys was 1.7 with a standard deviation of 0.8. Conduct a hypothesis test to determine if the means are approximately the same or if the girls' mean is higher than the boys' mean. Which of the following tests is appropriate? two-tailed t-score test for Students' t-distribution left-tailed t-score test for Students' t-distribution right-tailed z-score test for normal distribution (z) two-tailed z-score test for normal distribution (z) two-tailed z-score test for normal distribution (z) right-tailed t-score test for Students' t-distribution Question 7 1 pts When studying gender dierences in teen behavior, researchers have collected data implying that teenage girls use more ring tones on their cellular phones than teenage boys do. In one particular study of 40 randomly chosen teenage girls and boys (20 of each) with cellular phones, the mean number of ring tones for the girls was 3.2 with a standard deviation of 1.5. The mean for the boys was 1.7 with a standard deviation of 0.8. Conduct a hypothesis test to determine if the means are approximately the same or if the girls' mean is higher than the boys' mean. What is the test statistic for this hypothesis test? More than 4.00 Between 3.0 and 3.5 Between 3.6 and 4.0 Less than 3.0 Question 8 1 pts When studying gender dierences in teen behavior, researchers have collected data implying that teenage girls use more ring tones on their cellular phones than teenage boys do. In one particular study of 40 randomly chosen teenage girls and boys (20 of each) with cellular phones, the mean number of ring tones for the girls was 3.2 with a standard deviation of 1.5. The mean for the boys was 1.7 with a standard deviation of 0.8. Conduct a hypothesis test to determine if the means are approximately the same or if the girls' mean is higher than the boys' mean. How many degrees of freedom (df) should be used when looking up p on a table or calculator? 39 38 20 40 2 19 Question 9 1 pts When studying gender dierences in teen behavior, researchers have collected data implying that teenage girls use more ring tones on their cellular phones than teenage boys do. In one particular study of 40 randomly chosen teenage girls and boys (20 of each) with cellular phones, the mean number of ring tones for the girls was 3.2 with a standard deviation of 1.5. The mean for the boys was 1.7 with a standard deviation of 0.8. Conduct a hypothesis test to determine if the means are approximately the same or if the girls' mean is higher than the boys' mean. What is the p-value? Between 0 and .0003 Between .0003 and .0006 Between .0010 and .9900 Between .0006 and .0010 Between .9900 and 1 Question 10 1 pts When studying gender dierences in teen behavior, researchers have collected data implying that teenage girls use more ring tones on their cellular phones than teenage boys do. In one particular study of 40 randomly chosen teenage girls and boys (20 of each) with cellular phones, the mean number of ring tones for the girls was 3.2 with a standard deviation of 1.5. The mean for the boys was 1.7 with a standard deviation of 0.8. Conduct a hypothesis test to determine if the means are approximately the same or if the girls' mean is higher than the boys' mean. Do you reject or not reject the null hypothesis at 5% signicance level, and why? We do not reject the null hypothesis because p-value is less than 5%. We reject the null hypothesis because p-value is greater than 5%. We reject the null hypothesis because p-value is less than than 5%. We do not reject the null hypothesis because p-value is greater than 5%. Question 11 1 pts When studying gender dierences in teen behavior, researchers have collected data implying that teenage girls use more ring tones on their cellular phones than teenage boys do. In one particular study of 40 randomly chosen teenage girls and boys (20 of each) with cellular phones, the mean number of ring tones for the girls was 3.2 with a standard deviation of 1.5. The mean for the boys was 1.7 with a standard deviation of 0.8. Conduct a hypothesis test to determine if the means are approximately the same or if the girls' mean is higher than the boys' mean. Which is a meaningful conclusion about this hypothesis test? At the 5% signicance level, there is sucient evidence to conclude that the mean number of ringtones for girls is dierent from that for boys. At the 5% signicance level, there is sucient evidence to conclude that the mean number of ringtones for girls is no dierent from that for boys. At the 5% signicance level, there is sucient evidence to conclude that the mean number of ringtones for girls is higher than that for boys. At the 5% signicance level, there is sucient evidence to conclude that the mean number of ringtones for girls is lower than that for boys. Question 12 1 pts The mean age for all Boiling Goat College students for a recent fall term was 33.2. The population standard deviation has been pretty consistent at 15. Suppose that 25 students were randomly selected. The mean age for the sample was 30.4. Construct a 95% condence interval for the sample mean. How much area is in each tail of the normal distribution (/2)? .10 .025 .05 .95 Question 13 1 pts The mean age for all Boiling Goat College students for a recent fall term was 33.2. The population standard deviation has been pretty consistent at 15. Suppose that 25 students were randomly selected. The mean age for the sample was 30.4. Construct a 95% condence interval for the sample mean. Although the sample is only 25, please use the z distribution and not the t. What is the z-score associated with a 95% CI? Less than 1.50 Between 1.51 and 1.75 Between 1.76 and 2.00 Between 2.01 and 2.50 More than 2.50 Question 14 1 pts The mean age for all Boiling Goat College students for a recent fall term was 33.2. The population standard deviation has been pretty consistent at 15. Suppose that 25 students were randomly selected. The mean age for the sample was 30.4. Construct a 95% condence interval for the sample mean. Although the sample is only 25, please use the z distribution and not the t. What's the estimated margin of error? In other words, what's that +/- number we need to construct the condence interval? Less than 5.50 More than 6.50 Between 5.51 and 5.75 Between 5.76 and 6.00 Between 6.01 and 6.50 Question 15 1 pts The mean age for all Boiling Goat College students for a recent fall term was 33.2. The population standard deviation has been pretty consistent at 15. Suppose that 25 students were randomly selected. The mean age for the sample was 30.4. Construct a 95% condence interval for the sample mean. Although the sample is only 25, please use the z distribution and not the t. Which of the numbers in this graph is incorrect? 36.28 95% 24.52 30.4 all of the above numbers in the graph are correct .025 Question 16 1 pts The following questions will require the use of STATA. The data, from the General Social Survey, are in the data le homework5.dta. Here are the variables: age (age in years), married (whether or not respondents are married, coded as 0 if not married, 1 if married), tvhours (hours of TV watched per day). What's the mean age of this sample? 47 18 51 43 46 Question 17 1 pts The following questions will require the use of STATA. The data, from the General Social Survey, are in the data le homework5.dta. Here are the variables: age (age in years), married (whether or not respondents are married, coded as 0 if not married, 1 if married), tvhours (hours of TV watched per day). What's the median age of this sample? 43 47 18 46 51 Question 18 1 pts The following questions will require the use of STATA. The data, from the General Social Survey, are in the data le homework5.dta. Here are the variables: age (age in years), married (whether or not respondents are married, coded as 0 if not married, 1 if married), tvhours (hours of TV watched per day). What's the age at the 90 percentile in these data? 65 89 79 60 72 Question 19 1 pts The following questions will require the use of STATA. The data, from the General Social Survey, are in the data le homework5.dta. Here are the variables: age (age in years), married (whether or not respondents are married, coded as 0 if not married, 1 if married), tvhours (hours of TV watched per day). What's the standard deviation of age? 43 18 0 10 12 Question 20 1 pts The following questions will require the use of STATA. The data, from the General Social Survey, are in the data le homework5.dta. Here are the variables: age (age in years), married (whether or not respondents are married, coded as 0 if not married, 1 if married), tvhours (hours of TV watched per day). What percentage of respondents are retirement age (that is, 65 or older)? 19 81 30 50 43 Question 21 1 pts The following questions will require the use of STATA. The data, from the General Social Survey, are in the data le homework5.dta. Here are the variables: age (age in years), married (whether or not respondents are married, coded as 0 if not married, 1 if married), tvhours (hours of TV watched per day). What percentage of respondents are married? 49 51 30 43 20 Question 22 1 pts The following questions will require the use of STATA. The data, from the General Social Survey, are in the data le homework5.dta. Here are the variables: age (age in years), married (whether or not respondents are married, coded as 0 if not married, 1 if married), tvhours (hours of TV watched per day). Conduct a t-test of television viewing by marital status. What is the value of t? 0 2.68 2.97 .16 .31 Question 23 1 pts The following questions will require the use of STATA. The data, from the General Social Survey, are in the data le homework5.dta. Here are the variables: age (age in years), married (whether or not respondents are married, coded as 0 if not married, 1 if married), tvhours (hours of TV watched per day). Conduct a t-test of television viewing by marital status. What is the two-tailed p value? .004 1 .008 0 Question 24 1 pts The following questions will require the use of STATA. The data, from the General Social Survey, are in the data le homework5.dta. Here are the variables: age (age in years), married (whether or not respondents are married, coded as 0 if not married, 1 if married), tvhours (hours of TV watched per day). Conduct a t-test of television viewing by marital status. What is the one-tail p value for the hypothesis that single people watch more TV than married people? .004 .008 1 0 Question 25 1 pts The following questions will require the use of STATA. The data, from the General Social Survey, are in the data le homework5.dta. Here are the variables: age (age in years), married (whether or not respondents are married, coded as 0 if not married, 1 if married), tvhours (hours of TV watched per day). Conduct a t-test of television viewing by marital status. Which of the following represents the null hypothesis? di = mean(0) - mean(1), di = 0 None of the above represents the null hypothesis di = mean(0) - mean(1), di < 0 di = mean(0) - mean(1), di != 0 di = mean(0) - mean(1), di > 0 Question 26 1 pts The following questions will require the use of STATA. The data, from the General Social Survey, are in the data le homework5.dta. Here are the variables: age (age in years), married (whether or not respondents are married, coded as 0 if not married, 1 if married), tvhours (hours of TV watched per day). Which of the following claims is true? Married people watch more TV than single people It cannot be determined whether married or single people watch more TV Married and single people watch the same amount of TV a day Single people watch more TV than married people Question 27 1 pts Suppose a marketing company randomly surveyed 200 households and found that in 120 of them the woman made the majority of the purchasing decisions. We are interested in constructing a 95% condence interval for the proportion of households in which women make the majority of purchasing decisions. What's the estimated margin of error? In other words, what's that +/- number we need to construct the condence interval? Between .05 and .075 Between 1.001 and 1.025 Less than .05 More than 1.025 Between .076 and 1.000 Question 28 1 pts Suppose a marketing company randomly surveyed 200 households and found that in 120 of them, the woman made the majority of the purchasing decisions. We are interested in constructing a 95% condence interval for the proportion of households in which women make the majority of purchasing decisions. What is the lower bound of the condence interval associated with a 95% condence interval for this proportion? Between .55 and .575 More than .625 Between .576 and .600 Less than .55 Between .601 and .625 Question 29 1 pts Suppose a marketing company randomly surveyed 200 households and found that in 120 of them, the woman made the majority of the purchasing decisions. We are interested in constructing a 95% condence interval for the proportion of households in which women make the majority of purchasing decisions. What is the upper bound of the condence interval associated with a 95% condence interval for this proportion? Less than .55 More than .625 Between .601 and .625 Between .55 and .575 Between .576 and .600 Question 30 1 pts Marketing companies are interested in knowing what percentage of women make the majority of household purchasing decisions. When designing a study to determine this proportion, what is the minimum number you would need to survey to be 90% condent that the population proportion is estimated to within .05? Between 151 and 175 Between 201 and 250 Between 176 and 200 Less than 150 More than 250 Saving... 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Between 3.6 and 4.0 8. 38 9. Between 0 and .0003 10. We reject the null hypothesis because p-value is less than 5%. 11. At the 5% significance level, there is sufficient evidence to conclude that the mean number of ringtones for girls is higher than that for boys. 12. .025 13. Between 1.76 and 2.00 14. Between 5.76 and 6.00 15. all of the above numbers in the graph are correct 16. 47 17. 43 18. 72 19. 18 20. 19 21. 51 22. 2.68 23. 0.008 24. 0.004 25. diff = mean(0) - mean(1), diff = 0 26. Single people watch more TV than married people 27. Between .05 and .075 28. Less than .55 29. More than .625 30. 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Between 3.6 and 4.0 8. 38 9. Between 0 and .0003 10. We reject the null hypothesis because p-value is less than 5%. 11. At the 5% significance level, there is sufficient evidence to conclude that the mean number of ringtones for girls is higher than that for boys. 12. .025 13. Between 1.76 and 2.00 14. Between 5.76 and 6.00 15. all of the above numbers in the graph are correct 16. 47 17. 43 18. 72 19. 18 20. 19 21. 51 22. 2.68 23. 0.008 24. 0.004 25. diff = mean(0) - mean(1), diff = 0 26. Single people watch more TV than married people 27. Between .05 and .075 28. Less than .55 29. More than .625 30. More than 250

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