Question: Use Newton's Method to find solutions accurate to within 10^-5 to the problem Sin 3x + 3 e^ -2x (sin x ) - 3e^-x (sin2x)

Use Newton's Method to find solutions accurate to within 10^-5 to the problem

Sin 3x + 3 e^ -2x (sin x ) - 3e^-x (sin2x) - e^ -3x = 0 for 3<_ x <_ 4

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