Use Taylor’s method of order two to approximate the solutions for each of the following initial-value problems.

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y-te-2y, 0t1, y(0)=0, with h = 0.5 y = 1+(-y), 213, y(2) = 1, with h = 0.5 y = 1+y/t, 1t2, y(1)=2, with h = 0.25 b. c. d. y = cos 2t+sin 3t, 0t 1, y(0) = 1, with h = 0.25 y-te-2y, 0t1, y(0)=0, with h = 0.5 y = 1+(-y), 213, y(2) = 1, with h = 0.5 y = 1+y/t, 1t2, y(1)=2, with h = 0.25 b. c. d. y = cos 2t+sin 3t, 0t 1, y(0) = 1, with h = 0.25

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The detailed answer for the above question is provided below Step 1 a For the initialvalue problem 1 the given as given in Exercise3a of 52 exact solution is 2 Compare the given differential equation ... View the full answer