Question: Use the graph below to answer this question ACTIVITY PREDECESSOR NORMAL TIME NORMAL COST CRASH TIME CRASH COST A - 7 days $6,000 6 days
Use the graph below to answer this question
| ACTIVITY | PREDECESSOR | NORMAL TIME | NORMAL COST | CRASH TIME | CRASH COST |
| A | - | 7 days | $6,000 | 6 days | $6,600 |
| B | A | 4 days | $1,200 | 2 days | $3,000 |
| C | B | 11 days | $4,000 | 9 days | $6,000 |
a. What action is the least expensive if you were to crash and reduce the critical path by 1 day/
b. Assuming no other paths are critical, what would you do to reduce the critical path by one additional day - the least expensive action?
c. What is the total cost of this 2-day reduction?
Group of answer choices
a: Reduce a = $600; b: Reduce b & c = $1900; c: Total Cost = $2500
a: Reduce a = $600; b: Reduce b = $900; c: Total Cost = $1500
a: Reduce a = $600; b: Reduce b = $1800; c: Total Cost = $2400
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