use the intervals object from this problem. $($Interval Data Type$)$ Define a data type called Interval in interval.py that represents a closed $1$D interval. The data type must support the following API: interval.Interval Interval$($lbound$,$ rbound$)$ constructs an interval i given its lower and upper bounds i$.$lower$()$ returns the lower bound of i i$.$upper$()$ i$.$contains$($x$)$ i$.$intersects$($j$)$ str$($i$)$ returns the upper bound of i returns True if i contains the value x$,$ and False otherwise returns True if i intersects interval j$,$ and False otherwise returns a string representation of i as $[$lbound$,$ rbound$].$ Use this data type for the interval solution. Instance variables$-$ Lower bound of the interval, $\_$lbound $($float$)-$ Upper bound of the interval, $\_$rbound $($float$)\_\_$init$\_\_($self$,$ lbound, ubound$)-$ Initialize the instance variables to the values of the corresponding parameters lower$($self$)-$ Return the value of the instance variable $\_$lbound upper$($self$)-$ Return the value of the instance variable $\_$ubound contains$($self$,$ x$)-$ Return True if the interval self contains x and False otherwise intersects$($self$,$ other$)-$ Return True if the interval self intersects the interval other and False otherwise $\_\_$str$\_\_($self$)-$ Return a string representation of the interval self