Use the Laplace transform to solve the following initial value problem: y' - 6y - 27y =0 y(0) = -3, y (0) =2 First, using Y for the Laplace transform of y(t), i.e., Y = Cty(t)} , find the equation you get by taking the Laplace transform of the differential equation L(y") -6L(y')-27L(y) 0 Now solve for Y(s) = (-3s + 16)/((s-9)(s+3)) and write the above answer in its partial fraction decomposition, Y(s) = A B + where a