Question: Use the References to access important values if needed for this question. For the following reaction, 2.58 grams of methane (CH4) are allowed to react

Use the References to access important values if needed for this question. For the following reaction, 2.58 grams of methane (CH4) are allowed to react with 29.7grams of carbon tetrachloride. methane (CH4)(g)+ carbon tetrachloride (g) dichloromethane (CH2Cl2)(g) What is the maximum mass of dichloromethane (CH2Cl2) that can be formed? Mass=9 What is the FORMULA for the limiting reactant? What mass of the excess reagent remains after the reaction is complete? Mass=9

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