Using JavaScript create a function called sumOddInts that accepts a positive integer n and returns the sum of the odd numbers from 1 to n. Your function must test to make sure the number is greater than or equal to 0 using a conditional (you may be able to avoid the conditional if you write the loop right.) For numbers less than 0, return 0.

Output Specifications:

sumOddInts(12); <- 36

sumOddInts(0); <- 0

sumOddInts(-17); <- 0

sumOddInts(3); <- 4