Using lab $7$ with a two$-$day lead time $($all original values$),$ if we increased the min and max by $5\%$ each $($from original values$),$ the total cost would be However, if we increased the min and max by $10\%$ each $($from original values$),$ the total cost would be Lastly, if we increased the min and max by $15\%$ each $($from original values$),$ the total cost would be $x.$ Therefore, increasing the min and max by $*$ would be the best scenario to minimize the overall cost, while increasing the min and max by scenario.

wordld be the worst

rat

$$254,508$$$239,868$

$10\%$

$5\%$

$15\%$