Question: Using the following table of points and using the polynomial method Newton-Gregory interpolants, Calculate the value of Y for X = 0.25 X = 0.35

Using the following table of points and using the polynomial method Newton-Gregory interpolants, Calculate the value of Y for X = 0.25 X = 0.35 (The difference table, the difference vector and the calculations necessary to obtain the requested results must be provided).

X Y

0 1.000000

0.1 0.799950

0.2 0.599200

0.3 0.395953

0.4 0.187227

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