Using the list names and alphaCount defined below, write a Python program that will

Display a string that consists of the first letter and last letter from each of the entries in n the list names

The output should look like EdAsNn etc. use the + operator or the append() function from prior lab

Display list names with all the names reversed that is display

dilcuE, sedemihcrA etc.

Display the total number of characters in the list Hint: Sum the lengths of each name

In the prior lab we determined the number of vowels in a list. For this lab, display the number of consonants (non-vowels) Use your result from 3, and subtract number of vowels

Display the list alphaCount which contains the number of each letter in the list NOTE case A and a are to be considered the same. See code below that starts with alphaCnt (There are eight A in the list ) as well as the code

alphaCount == [8, 2, . 0] i.e there are 8 A or a , there are 2 B or b . There are 0 Z or z

Display the average length of the strings in the list. Remember to use the results from 3 and divide by the number of names

use len() function

Once you have populated alphaCnt (== number of letters in the list names) display the letter that occurs the most in alphaCnt

Using the max function max(alphaCount) will return the largest number in alphaCount but not

the character associated with the max value ?

Sort the list names and display the median name

python code:

a = ["Euclid", "Archimedes", "Newton", "Descartes", "Fermat", "Turing", "Euler", "Einstein", "Boole", "Fibonacci", "Nash", "Wiles", "Cantor", "Gauss", "Plato"] # Initial list n == 15 print('0', a) j = 0 cnt = 1 for k in a: print(cnt, k, len(k), k[j], k[len(k) - 1]) # first letter and last letter in name  cnt = cnt + 1 s = 0 letter = 'i' for name in a: r = name.count(letter) s = s + r print("the number of i is ", s) s = 'TuringAabcdefghijklmnopqrstuvwxyz' print(' ord values for characters ') print('1 ',ord('A')-ord('A')) print('2 ',ord('B')-ord('A')) print('3 ',ord('C')-ord('A')) print('26 ',ord('Z')-ord('A')) alphaCnt = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] # 26 zeros store n of each uppercase letter for ch in s: ## looping in this way, ch will be 'T', then 'u', ... through the string  x = ord(ch.upper()) - ord('A') # to uppercase; determine place in alphaCnt  print(ch, ' ord value == ', x) alphaCnt[x] = alphaCnt[x] + 1 print('alphaCnt == ', alphaCnt) # number of A, B etc characters in s