V= ( - 1010. 2 V = - 2 m/s = ( - 2)0. 2 X = 6. 4 2. A student finds that it takes 0.20s for a ball to pass through photogates placed 0.3m apart on a level ramp. The end of the ramp is 0.92 m above the floor. Where could a coin be placed so that the ball directly strikes the coin on impact with the ground? photogates 4 - 6 . 2 table 0. 4 m away 0.12 floor 3. Suppose now that the same ball, released from the same ramp (0.92m high) struck a coin on the floor placed 0.25m from the end of the ramp. a. What was the ball's horizontal velocity? b. How long did it take for the ball to pass through the photogates? V x = (0.25 ) +