Question: VDW : P=(RT/V-b)-(a/V^2) At some specific temperature T, use VDW to find poles on the graph. I can't understand this: Q1: At a certain temperature

VDW :

P=(RT/V-b)-(a/V^2)

At some specific temperature T, use VDW to find poles on the graph.

I can't understand this:

Q1: At a certain temperature T, there are two poles, so why is the cubic equation for V? Isn't it possible to know the two poles only when the quadratic equation for V comes out??

Q2:Please tell me how to find the two poles

P=VbRTV2aUDW(Vp)T=(Vb)2RT+V32q=0RT joole

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