We can now find

f$($x$),$

which is given by the general antiderivative of

f$($x$)=2$x $+15$x$24$x$3+14,$

To do so$,$ we refer again to the following antidifferentiation formulas.

A function of the form

g$($x$)+$ h$($x$)$

will have the particular antiderivative

G$($x$)+$ H$($x$).$

A function of the form

ch$($x$)$

where c is a constant will have the particular antiderivative

cH$($x$).$

A function of the form

xn

where

n $1$

will have a particular antiderivative of the form

xn $+1$n $+1$

Applying these formulas to find the general antiderivative of

f$($x$)=2$x $+15$x$24$x$3+14$

and letting D represent the arbitrary constant gives the following result.

f$($x$)=$