Question: What, if anything, is wrong with the following statement? Since n = O(n), 2n = O(n), ..., we have sigma^n_k=1 kn = sigma^n_k=1 O(n) =

What, if anything, is wrong with the following statement? Since n

What, if anything, is wrong with the following statement? Since n = O(n), 2n = O(n), ..., we have sigma^n_k=1 kn = sigma^n_k=1 O(n) = O(n^2)

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