Question: What is the third-order polynomial function in joint-space to move a single rotary joint from 0-15 degrees in a smooth manner to 0 =
What is the third-order polynomial function in joint-space to move a single rotary joint from 0-15 degrees in a smooth manner to 0 = 75 degrees in 3 seconds: (A) 15+2012+ 4.440 (D) 15+20t2-4.44t (B) 15 + 25t2 +6.11t (E) 15+25t-6.11t (C) 15+10t + 1.11t (F) 15 + 10t-1.11t What is the third-order polynomial function in joint-space to move a single rotary joint from 0-15 degrees in a smooth manner to 0 = 75 degrees in 3 seconds: (A) 15+2012+ 4.440 (D) 15+20t2-4.44t (B) 15+ 25t2 +6.11t (E) 15+25t-6.11t (C) 15+10t + 1.11t (F) 15+10t-1.11t
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
