Question: When a process first enters the system, it is placed in RQ 0 . After its first preemption, when it returns to the Ready state,

When a process first enters the system, it is placed in RQ0. After its first preemption, when it returns to the Ready state, it is placed in RQ1(the highest priority queue). Each subsequent time that it is preempted, it is demoted to the next low-priority queue. Within each queue, except the lowest-priority queue, a simple FCFS mechanism is used. Once in the lowest-priority queue, a process cannot go lower; but is returned to this queue repeatedly until it completes execution. Thus, this queue is treated in a round-robin fashion.

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