Question: When compiling the code below, what is the expected outcome? #include int main ( void ) { int i = 1 4 ; double x

When compiling the code below, what is the expected outcome?
#include
int main(void){
int i=14;
double x=4.5;
printf("%d %lf
", x, i);
return 0;
}
Group of answer choices
You might get a warning message.
You will get a compilation error.
There is nothing wrong with this code.
There is nothing wrong, as long as the option '-std=c99' is used for compilation.

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