For the circuit shown below Vs = 6V, IS1 = 3A, IS2 = 0.08cos(5t), V2 =...

 

Transcribed Image Text:

For the circuit shown below Vs = 6V, IS1 = 3A, IS2 = 0.08cos(5t), V2 = 2i₂²+4i₁ V₁ , ₁ = V1/8 - V2/8 a) Find the operating points of V1, i₁, V2, i2. (Take the positive root as the solution of the second degree equation. b) Make small signal analysis and approximate solutions Vn(t)= VnQ + Vn(t) and in(t) = InQ + in(t) (n=1, 2) + | Vs i1 + V1 3-T + V2 i2 IS1 4 IS2 A For the circuit shown below Vs = 6V, IS1 = 3A, IS2 = 0.08cos(5t), V2 = 2i₂²+4i₁ V₁ , ₁ = V1/8 - V2/8 a) Find the operating points of V1, i₁, V2, i2. (Take the positive root as the solution of the second degree equation. b) Make small signal analysis and approximate solutions Vn(t)= VnQ + Vn(t) and in(t) = InQ + in(t) (n=1, 2) + | Vs i1 + V1 3-T + V2 i2 IS1 4 IS2 A