When the ball is at an angle $33\mathrm{.}7$ to the vertical, it has a tangential acceleration of magnitude g sin $($produced by the tangential component of the force m$$g$).$ Therefore, at

$11$

$=33\mathrm{.}7,$ using the formula a obtain a $=5\mathrm{.}43748$ m$/$s$2.$

Find the magnitude of the total accelera$-$ tion at $=33\mathrm{.}7.$

Answer in units of m$/$s$2.$