why, in number (b), i got why -infinity is got in x approaches to -6^- and so does in -6^+ as well! but when x approaches to 6^-, why isnt it becoming negative infinity since its shift to left sign and why result of 6^+ became negative infinity ??

Previous Problem Problem List Next Problem (1 point) This problem has two parts. The second part will appear after you answer the first part correctly. (a) What are the vertical asymptotes of f (x) = - -3x2 X2 - 36 -? Your answer should be a number, a list of numbers separated by commas, or None. Vertical asymptotes at x = -6,6 (b) Find the following left- and right-hand limits at the vertical asymptote x = -6. Enter | for co, -| for -co, or DNE for does not exist. lim -3x2 -3x2 T x--6- X2 - 36 lim x->-6+ x2 - 36 Find the following left- and right-hand limits at the vertical asymptote x = 6. lim -3x2 x-6- X2 - 36 lim -3x2 T x-6+ x2 - 36 Note: You can earn partial credit on this problem. Preview My Answers Check Answers