Question: With a slight change in notation the transform L{f'(t) = s F(s) f(0) is the same as L{f'(t) = %3D s Lff(t)} f(0). With

With a slight change in notation the transform L{f'(t) = s F(s)

With a slight change in notation the transform L{f'(t) = s F(s) f(0) is the same as L{f'(t) = %3D s Lff(t)} f(0). With f(t) be used to evaluate {teat}. teat, discuss how this result in conjunction with L{eat} = can D-S

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