Question: (a) With a slight change in notation the transform in (6) is the same as With f(t) = te at , discuss how this result

(a) With a slight change in notation the transform in (6) is the same as

L{f'(1)} = sL{f(0) - f(0).


With f(t) = teat, discuss how this result in conjunction with (c) of Theorem 7.1.1 can be used to evaluate ℒ{teat}.

(b) Proceed as in part (a), but this time discuss how to use (7) with f (t) = t sin kt in conjunction with (d) and (e) of Theorem 7.1.1 to evaluate ℒ{t sin kt}.

L{f'(1)} = sL{f(0) - f(0).

Step by Step Solution

3.55 Rating (173 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

ANSWER a Starting with the given transform Lf1 sLf0 f0 We can rewrite it ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related A First Course in Differential Equations Questions!