Write in Python, please! Thank you!

Below is the test case and the result should be printed out.

4 Shape Function Turn in a file named proj06_shape.py. Inside it, declare a function proj06_shape(), which takes no parameters. (Helper functions are encouraged!) Your function must return the following shape (remember, the objects in this diagram are arrays, not linked lists): return this None (0,0) (1,0) (2,0) (3,0) (0,1) (1,1) (2,1) (3,1) (0,2) (1,2) (2,2) (3,2) None None None None Am I trying to use arrays to hint about how you could build a 2D grid with linked lists? I'll let you decide... import proj 06_shape def main(): print("Checking that proj06_shape() returns the proper structure") L = projo6_shape.proj06_shape() if len(L) != 2: print(f"ERROR: incorrect list length on the root node (expected: 2; got: {len(L)})") if len (L[0) != 2 or len (L[0][0]) != 2 or len(L[0][0][0])!= 2: print("ERROR: incorrect list length on one of the top-row nodes (other than the root node)") if Lolo [0][0] is not None: print("ERROR: The length of the top row is incorrect.") if type (L) != list or type (L[0]) != list or type (L[0][0])!= list or type (L[0][0][0]) != list: print("ERROR: One of the four top-row nodes is not an array object.") def check_col(col_root, col_num): if col_root [1] is None or len(col_root[1] ) != 2 or col_root [1][1] is None or len(col_root[1][1] ) != 2 or col_root [1][1][1] is None or len(col_root[1][1][1]) != 2 or col_root[1][1][1][1] is not None: print(f"ERROR: One of the elements in column [col_num} has the wrong length, or has the wrong value in [1]") if col_root[1] [0] != (col_num,) or col_root[1][1] [0] != (col_num, 1) or I col_root[1][1][1][0] != (col_num, 2): print(f"ERROR: One of the elements in column {col_num} has the wrong value in [0]") check_col(L, check_col(L[0], 1) check_col(L[O] [O], 2) check_col(L[0][0][0], 3) print) print("TESTCASE COMPLETED") Checking that proj06_shape () returns the proper structures TESTCASE COMPLETED 4 Shape Function Turn in a file named proj06_shape.py. Inside it, declare a function proj06_shape(), which takes no parameters. (Helper functions are encouraged!) Your function must return the following shape (remember, the objects in this diagram are arrays, not linked lists): return this None (0,0) (1,0) (2,0) (3,0) (0,1) (1,1) (2,1) (3,1) (0,2) (1,2) (2,2) (3,2) None None None None Am I trying to use arrays to hint about how you could build a 2D grid with linked lists? I'll let you decide... import proj 06_shape def main(): print("Checking that proj06_shape() returns the proper structure") L = projo6_shape.proj06_shape() if len(L) != 2: print(f"ERROR: incorrect list length on the root node (expected: 2; got: {len(L)})") if len (L[0) != 2 or len (L[0][0]) != 2 or len(L[0][0][0])!= 2: print("ERROR: incorrect list length on one of the top-row nodes (other than the root node)") if Lolo [0][0] is not None: print("ERROR: The length of the top row is incorrect.") if type (L) != list or type (L[0]) != list or type (L[0][0])!= list or type (L[0][0][0]) != list: print("ERROR: One of the four top-row nodes is not an array object.") def check_col(col_root, col_num): if col_root [1] is None or len(col_root[1] ) != 2 or col_root [1][1] is None or len(col_root[1][1] ) != 2 or col_root [1][1][1] is None or len(col_root[1][1][1]) != 2 or col_root[1][1][1][1] is not None: print(f"ERROR: One of the elements in column [col_num} has the wrong length, or has the wrong value in [1]") if col_root[1] [0] != (col_num,) or col_root[1][1] [0] != (col_num, 1) or I col_root[1][1][1][0] != (col_num, 2): print(f"ERROR: One of the elements in column {col_num} has the wrong value in [0]") check_col(L, check_col(L[0], 1) check_col(L[O] [O], 2) check_col(L[0][0][0], 3) print) print("TESTCASE COMPLETED") Checking that proj06_shape () returns the proper structures TESTCASE COMPLETED