x P(X= The number of customers per day for a car retailer is distributed as below:...

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x P(X= The number of customers per day for a car retailer is distributed as below: 0 1 2 3 4 0.28 0.14 0.04 0.02 = x) 0.52 Find the a) Expected value E[X], b) Variance and standard deviation of customers per day. c) If the profit per customer (Y) can be expressed as Y-300X+100 $, what is the expected value and variance of Y? x P(X= The number of customers per day for a car retailer is distributed as below: 0 1 2 3 4 0.28 0.14 0.04 0.02 = x) 0.52 Find the a) Expected value E[X], b) Variance and standard deviation of customers per day. c) If the profit per customer (Y) can be expressed as Y-300X+100 $, what is the expected value and variance of Y?

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ANSWER a The expected value of X is EX 14 customers per day b The variance of X is VarX 056 customer... View the full answer