$x(x+1)\frac{dy}{dx}+xy=1.,y(e)=1$

Possible Answers

$($a$)y=\frac{lnx-e}{x+1}$

$($b$.)y=\frac{lnx+e}{x+1}$

$($c$)y=\frac{lnx+e}{x-1}$

$($d$.)y=\frac{lnx-e}{x-1}$

$($e$)$ None of the above