You are given the equation used to solve a problem.

$12(1500$kg$)(5\mathrm{.}0$m$/$s$)2+(1500$kg$)(9\mathrm{.}80$m$/$s$2)(10$m$)=12(1500$kg$)$v$2$i$+(1500$kg$)(9\mathrm{.}80$m$/$s$2)(0$m$)12(1500$kg$)(5\mathrm{.}0$m$/$s$)2+(1500$kg$)(9\mathrm{.}80$m$/$s$2)(10$m$)=12(1500$kg$)$vi$2+(1500$kg$)(9\mathrm{.}80$m$/$s$2)(0$m$)$

Part A

Choose a realistic problem for which this is the correct equation.

A $1500$ kgkg auto rides $10$ mm with a speed of $5\mathrm{.}0$ m$/$sm$/$s and then coasts down a hill. What speed will the auto have at the bottom of the hill?A $1500$ kgkg auto coasts up a $10\mathrm{.}0$ mm high hill and reaches the top with a speed of $5\mathrm{.}0$ m$/$sm$/$s$.$ What initial speed must the auto have had at the bottom of the hill?A $1500$ kgkg auto coasts down a hill with and then rides $10$ mm with a speed of $5\mathrm{.}0$ m$/$sm$/$s$.$ What speed must the auto have had at the top of the hill?A $1500$ kgkg auto coasts up a $10\mathrm{.}0$ mm high hill with an initial speed of $5\mathrm{.}0$ m$/$sm$/$s$.$ What speed will the auto have at the top of the hill?