You connect two capacitors $C_1=15pF$ and $C_2=30pF$ in series across a $1\mathrm{.}5-$V battery. The potential difference across capacitor $C_1$ is approximately

$0\mathrm{.}50$ V $.$

$1\mathrm{.}0$ V $.$

$1\mathrm{.}5$ V

$0\mathrm{.}33$ V $.$

$0\mathrm{.}67$ V $.$