You pour out 260 g of tea, (specific heat c = 1.00ca. g K' same as...

 

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You pour out 260 g of tea, (specific heat c = 1.00ca. g K' same as H20), pretty hot to start, T; =331 K. However, you also want to sweeten it with some honey, mass mh =154g, right out of the refrigerator at temperature T; = 277 K. Honey's specific heat is c = 0.64 cal Calculate the thermal equilibrium of the tea with honey. Type in the equilibrium temperature to the nearest Kelvin. E.g., if your answer it 233.588 K, then type in 234. You pour out 260 g of tea, (specific heat c = 1.00ca. g K' same as H20), pretty hot to start, T; =331 K. However, you also want to sweeten it with some honey, mass mh =154g, right out of the refrigerator at temperature T; = 277 K. Honey's specific heat is c = 0.64 cal Calculate the thermal equilibrium of the tea with honey. Type in the equilibrium temperature to the nearest Kelvin. E.g., if your answer it 233.588 K, then type in 234.

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Using Energy conservation Net Energy absorbedreleased by masses 0 Q1 Q2 0 e... View the full answer