Question: Your program takes as input a 3 - variable Boolean function in the form of a sum - of - products. For example, the input

Your program takes as input a 3-variable Boolean function in the form of a
sum-of-products. For example, the input can look like AB+ABC
+ABC. The double quotations are needed so that the is taken as
a regular character, negating the preceding variable, and not considered a
special character.
The evaluation of each term, e,g., ABC, is done in a separate function,
called, evalTerm(int A, int B, int C, char *term) that return the
Boolean value (0 or 1) of the corresponding term.
Your program should print the Boolean function followed by its truth
table.
#include
#include
// Function to evaluate a single term
int evalTerm(int A, int B, int C, char *term){
int result =1;
for (int i =0; i strlen(term); i++){
if (term[i]=='A' && !A){
result =0;
break;
} else if (term[i]=='B' && !B){
result =0;
break;
} else if (term[i]=='C' && !C){
result =0;
break;
}
}
return result;
}
// Function to print the truth table
void printTruthTable(char *function){
int A, B, C;
printf("Truth table of F
", function);
printf("A B C | F
");
printf("------|---
");
for (A =0; A =1; A++){
for (B =0; B =1; B++){
for (C =0; C =1; C++){
int result =0;
int numTerms =0; // Count the number of terms
char *term = strtok(function,"+");
while (term != NULL){
result += evalTerm(A, B, C, term);
numTerms++; // Increment the term count
term = strtok(NULL,"+");
}
printf("%d %d %d |%d
", A, B, C, result == numTerms ?1 : 0);
}
}
}
}
int main(int argc, char *argv[]){
if (argc 2){
printf("Truth table generator for 3-variable Boolean functions
", argv[0]);
printf("Usage:\"Enter a Boolean function as a sum of products\"
", argv[0]);
return 1;
}
printTruthTable(argv[1]);
return 0;
}
 Your program takes as input a 3-variable Boolean function in the

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