In the hand simulation of the simple processing system, suppose the drill press is taken down for burn-in maintenance at time 4 minutes, and it takes 4 minutes to do this work and bring it back up; it then stays up for the rest of the 20-minute simulation length. If there’s a part in service when the drill press goes down, it just sits there, its processing suspended until the drill press comes back up, when it’s resumed and needs just its remaining processing time (its processing does not have to start over from scratch). During the down time, the arrival process of new parts continues without regard to down time. Regard the drill press as being busy when it’s down, and def ne the time in system of a part to include the time it sits in the drill press but not being worked on if it’s unlucky enough to be in service when the drill press is taken down. Using the same input data as in Table