Question: If A is defined by A= $$begin{bmatrix} 1 & 1 & 0 & -1 2 & 1 & 0 & 1 1 &
If A is defined by A=
$$\begin{bmatrix}
1 & 1 & 0 & -1 \\
2 & 1 & 0 & 1 \\
1 & 1 & 0 & 2 \\
1 & -1 & 1 & 1
\end{bmatrix}$$
find det (A) and det (P'AP), where P is defined in Prob. 18, and show that the two are equal. This result demonstrates Theorem 1.8.7.
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