Question: Rework Problem 13.9 if the source voltage is a pulse of magnitude (mathrm{E}) and duration (tau / 10); that is, (e_{mathrm{G}}(t)=mathrm{E}left[u_{-1}(t)-u_{-1}(t-tau / 10) ight] .
Rework Problem 13.9 if the source voltage is a pulse of magnitude \(\mathrm{E}\) and duration \(\tau / 10\); that is, \(e_{\mathrm{G}}(t)=\mathrm{E}\left[u_{-1}(t)-u_{-1}(t-\tau / 10)\right] . \mathrm{Z}_{\mathrm{R}}=4 \mathrm{Z}_{c}\) and \(\mathrm{Z}_{\mathrm{G}}=\mathrm{Z}_{c} / 3\) are the same as in Problem 13.9.
Data From Problem 13.9:-
Draw the Bewley lattice diagram for Problem 13.5, and plot \(v(l / 3, t)\) versus time \(t\) for \(0 \leqslant t \leqslant 5 \tau\). Also plot \(v(x, 3 \tau)\) versus \(x\) for \(0 \leqslant x \leqslant l\).
Data From Problem 13.5:-
Rework Example 13.4 with \(\mathrm{Z}_{\mathrm{R}}=4 \mathrm{Z}_{c}\) and \(\mathrm{Z}_{\mathrm{G}}=\mathrm{Z}_{c} / 3\).
Data From Example 13.4:-

At the receiving end, ZR = Ze/3. At the sending end, eG(t) = Eu_1(t) and ZG = 2Zc. Determine and plot the voltage versus time at the center of the line.
Step by Step Solution
3.41 Rating (148 Votes )
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
