The impedance diagram of a three-phase four-bus power system is shown in Fig. 7.7.

If the lines of 2-4 and 1-3 are removed from the system, the network admittance matrix can be presented in the form of [Y \(\mathrm{Y}_{\text {Bus, }}\), \(\left.N_{\text {New }}ight]=\left[\mathrm{Y}_{\text {Bus }}ight]+\left[\Delta \mathrm{Y}_{\text {Bus }}ight]\). Determine \(\left[\Delta \mathrm{Y}_{\text {Bus }}ight]\).

1) \(j\left[\begin{array}{cccc}10 & 0 & 10 & 0 \\ 0 & 10 & 0 & 10 \\ 10 & 0 & 10 & 0 \\ 0 & 10 & 0 & 10\end{array}ight]\) p.u.

2) \(j\left[\begin{array}{cccc}10 & 0 & -10 & 0 \\ 0 & 10 & 0 & -10 \\ -10 & 0 & 10 & 0 \\ 0 & -10 & 0 & 10\end{array}ight]\) p.u.

3) \(j\left[\begin{array}{cccc}-10 & 0 & 10 & 0 \\ 0 & -10 & 0 & 10 \\ 10 & 0 & -10 & 0 \\ 0 & 10 & 0 & -10\end{array}ight]\) p.u.

4) \(j\left[\begin{array}{cccc}-10 & 0 & -10 & 0 \\ 0 & -10 & 0 & -10 \\ -10 & 0 & -10 & 0 \\ 0 & -10 & 0 & -10\end{array}ight]\) p.u.

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jo.1 p.u.. 3 Load j0.1 p.u 10.1 p. 10.1 p.u jo.1 p.u to 2 jo.1 p.u Load