A charge of +3 10 9 C is 50 cm from a charge of 5
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A charge of +3 × 10−9 C is 50 cm from a charge of −5 × 10−9 C. Find the magnitude and direction of the force on each charge.
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Given that q 1 3 10 9 c q 2 5 10 9 c Distance between them r 50cm 5 ...View the full answer
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