When the radium isotope 226 88 Ra undergoes alpha decay, the energy liberated is 4.87 MeV. (a)

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When the radium isotope ²²⁶₈₈ Ra undergoes alpha decay, the energy liberated is 4.87 MeV.

(a) Identify the resulting nuclide.

(b) The alpha particle has a KE of 4.78 MeV. Where do you think the other 0.09 MeV goes?

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The Physical Universe

ISBN: 978-0077862619

16th edition

Authors: Konrad B Krauskopf, Arthur Beiser

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Question Posted: Jan 08, 2019 12:56 PM

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When the radium isotope 226 88 Ra undergoes alpha decay, the energy liberated is 4.87 MeV. (a)

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a Rn a radon isotope b When the alpha par...View the full answer

The Physical Universe

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