The energy levels of the three-dimensional harmonic oscillator are given by E n1,n2,n3 = (n 1 +n
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The energy levels of the three-dimensional harmonic oscillator are given by En1,n2,n3 = (n1 +n2 +n3 + 3/2)ћω with n1,2,3 = 0, 1, . . .. Suppose three spin-1/2 fermions are trapped in a three-dimensional oscillator. What is the energy of the ground state? What is its degeneracy? (Remember that the degeneracy is the number of independent states with the same energy.) Extra challenge: What is the energy of the first excited state? What is its degeneracy?
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The ground state has energy 23252 112 There are six degenerate states of the for...View the full answer
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